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101300012455 = 520260002491
BaseRepresentation
bin101111001010111110…
…0111000010110100111
3100200110202211211002011
41132111330320112213
53124430300344310
6114311522455051
710214210620165
oct1362574702647
9320422754064
10101300012455
1139a63241764
1217771204487
139724c50295
144c8d986235
15297d42d78a
hex1795f385a7

101300012455 has 4 divisors (see below), whose sum is σ = 121560014952. Its totient is φ = 81040009960.

The previous prime is 101300012453. The next prime is 101300012477. The reversal of 101300012455 is 554210003101.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 554210003101 = 3471597146983.

It is not a de Polignac number, because 101300012455 - 21 = 101300012453 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101300012453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10130001241 + ... + 10130001250.

It is an arithmetic number, because the mean of its divisors is an integer number (30390003738).

Almost surely, 2101300012455 is an apocalyptic number.

101300012455 is a deficient number, since it is larger than the sum of its proper divisors (20260002497).

101300012455 is an equidigital number, since it uses as much as digits as its factorization.

101300012455 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20260002496.

The product of its (nonzero) digits is 600, while the sum is 22.

Adding to 101300012455 its reverse (554210003101), we get a palindrome (655510015556).

The spelling of 101300012455 in words is "one hundred one billion, three hundred million, twelve thousand, four hundred fifty-five".

Divisors: 1 5 20260002491 101300012455