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1013001130241 is a prime number
BaseRepresentation
bin11101011110110111001…
…00101001000100000001
310120211201210100021100022
432233123210221010001
5113044111242131431
62053211041503225
7133121053351562
oct16573344510401
93524653307308
101013001130241
1136067a802531
121443b0041b15
13746aa974b09
143705adc8169
151b53cd3d07b
hexebdb929101

1013001130241 has 2 divisors, whose sum is σ = 1013001130242. Its totient is φ = 1013001130240.

The previous prime is 1013001130201. The next prime is 1013001130279. The reversal of 1013001130241 is 1420311003101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 840696441025 + 172304689216 = 916895^2 + 415096^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1013001130241 is a prime.

It is not a weakly prime, because it can be changed into another prime (1013001130201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506500565120 + 506500565121.

It is an arithmetic number, because the mean of its divisors is an integer number (506500565121).

Almost surely, 21013001130241 is an apocalyptic number.

It is an amenable number.

1013001130241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1013001130241 is an equidigital number, since it uses as much as digits as its factorization.

1013001130241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1013001130241 its reverse (1420311003101), we get a palindrome (2433312133342).

The spelling of 1013001130241 in words is "one trillion, thirteen billion, one million, one hundred thirty thousand, two hundred forty-one".