10130011313033 has 2 divisors, whose sum is σ = 10130011313034. Its totient is φ = 10130011313032.

The previous prime is 10130011313029. The next prime is 10130011313077. The reversal of 10130011313033 is 33031311003101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9839244477049 + 290766835984 = 3136757^2 + 539228^2 .

It is a cyclic number.

It is not a de Polignac number, because 10130011313033 - 2² = 10130011313029 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10130011312996 and 10130011313014.

It is not a weakly prime, because it can be changed into another prime (10130011313533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065005656516 + 5065005656517.

It is an arithmetic number, because the mean of its divisors is an integer number (5065005656517).

Almost surely, 2^{10130011313033} is an apocalyptic number.

It is an amenable number.

10130011313033 is a deficient number, since it is larger than the sum of its proper divisors (1).

10130011313033 is an equidigital number, since it uses as much as digits as its factorization.

10130011313033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243, while the sum is 20.

Adding to 10130011313033 its reverse (33031311003101), we get a palindrome (43161322316134).

The spelling of 10130011313033 in words is "ten trillion, one hundred thirty billion, eleven million, three hundred thirteen thousand, thirty-three".