Base | Representation |
---|---|
bin | 11101011110110111001… |
… | …01011001111001101001 |
3 | 10120211201210201102202012 |
4 | 32233123211121321221 |
5 | 113044111320032111 |
6 | 2053211050045305 |
7 | 133121055144023 |
oct | 16573345317151 |
9 | 3524653642665 |
10 | 1013001330281 |
11 | 36067a929856 |
12 | 1443b0119835 |
13 | 746aaa14b95 |
14 | 3705b03b013 |
15 | 1b53cd7c48b |
hex | ebdb959e69 |
1013001330281 has 2 divisors, whose sum is σ = 1013001330282. Its totient is φ = 1013001330280.
The previous prime is 1013001330269. The next prime is 1013001330317. The reversal of 1013001330281 is 1820331003101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 622552560400 + 390448769881 = 789020^2 + 624859^2 .
It is a cyclic number.
It is not a de Polignac number, because 1013001330281 - 26 = 1013001330217 is a prime.
It is a super-2 number, since 2×10130013302812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1013001332281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506500665140 + 506500665141.
It is an arithmetic number, because the mean of its divisors is an integer number (506500665141).
Almost surely, 21013001330281 is an apocalyptic number.
It is an amenable number.
1013001330281 is a deficient number, since it is larger than the sum of its proper divisors (1).
1013001330281 is an equidigital number, since it uses as much as digits as its factorization.
1013001330281 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 1013001330281 its reverse (1820331003101), we get a palindrome (2833332333382).
The spelling of 1013001330281 in words is "one trillion, thirteen billion, one million, three hundred thirty thousand, two hundred eighty-one".
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