Base | Representation |
---|---|
bin | 101111001010111110… |
… | …1101101111101010001 |
3 | 100200110210020222021002 |
4 | 1132111331231331101 |
5 | 3124430324411032 |
6 | 114311531311345 |
7 | 10214212523255 |
oct | 1362575557521 |
9 | 320423228232 |
10 | 101300232017 |
11 | 39a63381716 |
12 | 177712ab555 |
13 | 9724cc91ba |
14 | 4c8da02265 |
15 | 297d473862 |
hex | 1795f6df51 |
101300232017 has 2 divisors, whose sum is σ = 101300232018. Its totient is φ = 101300232016.
The previous prime is 101300232013. The next prime is 101300232067. The reversal of 101300232017 is 710232003101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 74686877521 + 26613354496 = 273289^2 + 163136^2 .
It is a cyclic number.
It is not a de Polignac number, because 101300232017 - 22 = 101300232013 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 101300232017.
It is not a weakly prime, because it can be changed into another prime (101300232013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50650116008 + 50650116009.
It is an arithmetic number, because the mean of its divisors is an integer number (50650116009).
Almost surely, 2101300232017 is an apocalyptic number.
It is an amenable number.
101300232017 is a deficient number, since it is larger than the sum of its proper divisors (1).
101300232017 is an equidigital number, since it uses as much as digits as its factorization.
101300232017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 20.
Adding to 101300232017 its reverse (710232003101), we get a palindrome (811532235118).
The spelling of 101300232017 in words is "one hundred one billion, three hundred million, two hundred thirty-two thousand, seventeen".
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