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1013003255353 is a prime number
BaseRepresentation
bin11101011110110111011…
…00101111111000111001
310120211201221100020110011
432233123230233320321
5113044112313132403
62053211155221521
7133121110412335
oct16573354577071
93524657306404
101013003255353
11360680a24121
121443b08a78a1
13746ab23a18b
143705b3bc7c5
151b53d10ca6d
hexebdbb2fe39

1013003255353 has 2 divisors, whose sum is σ = 1013003255354. Its totient is φ = 1013003255352.

The previous prime is 1013003255347. The next prime is 1013003255387. The reversal of 1013003255353 is 3535523003101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 585428507689 + 427574747664 = 765133^2 + 653892^2 .

It is a cyclic number.

It is not a de Polignac number, because 1013003255353 - 29 = 1013003254841 is a prime.

It is not a weakly prime, because it can be changed into another prime (1013003255053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506501627676 + 506501627677.

It is an arithmetic number, because the mean of its divisors is an integer number (506501627677).

Almost surely, 21013003255353 is an apocalyptic number.

It is an amenable number.

1013003255353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1013003255353 is an equidigital number, since it uses as much as digits as its factorization.

1013003255353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20250, while the sum is 31.

Adding to 1013003255353 its reverse (3535523003101), we get a palindrome (4548526258454).

The spelling of 1013003255353 in words is "one trillion, thirteen billion, three million, two hundred fifty-five thousand, three hundred fifty-three".