101301232113131 has 2 divisors, whose sum is σ = 101301232113132. Its totient is φ = 101301232113130.

The previous prime is 101301232113127. The next prime is 101301232113143. The reversal of 101301232113131 is 131311232103101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 101301232113131 - 2² = 101301232113127 is a prime.

It is a super-2 number, since 2×101301232113131² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101301232113097 and 101301232113106.

It is not a weakly prime, because it can be changed into another prime (101301232113181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50650616056565 + 50650616056566.

It is an arithmetic number, because the mean of its divisors is an integer number (50650616056566).

Almost surely, 2^{101301232113131} is an apocalyptic number.

101301232113131 is a deficient number, since it is larger than the sum of its proper divisors (1).

101301232113131 is an equidigital number, since it uses as much as digits as its factorization.

101301232113131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 23.

Adding to 101301232113131 its reverse (131311232103101), we get a palindrome (232612464216232).

The spelling of 101301232113131 in words is "one hundred one trillion, three hundred one billion, two hundred thirty-two million, one hundred thirteen thousand, one hundred thirty-one".