Base | Representation |
---|---|
bin | 11101011110111001011… |
… | …01001000011100001011 |
3 | 10120211210010002201102001 |
4 | 32233130231020130023 |
5 | 113044131123230011 |
6 | 2053213001051431 |
7 | 133121404025566 |
oct | 16573455103413 |
9 | 3524703081361 |
10 | 1013020133131 |
11 | 36068a5016a6 |
12 | 1443b6486b77 |
13 | 746b1899426 |
14 | 3705d7334dd |
15 | 1b53e8437c1 |
hex | ebdcb4870b |
1013020133131 has 2 divisors, whose sum is σ = 1013020133132. Its totient is φ = 1013020133130.
The previous prime is 1013020133123. The next prime is 1013020133171. The reversal of 1013020133131 is 1313310203101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1013020133131 - 23 = 1013020133123 is a prime.
It is a super-2 number, since 2×10130201331312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1013020133099 and 1013020133108.
It is not a weakly prime, because it can be changed into another prime (1013020133171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506510066565 + 506510066566.
It is an arithmetic number, because the mean of its divisors is an integer number (506510066566).
Almost surely, 21013020133131 is an apocalyptic number.
1013020133131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1013020133131 is an equidigital number, since it uses as much as digits as its factorization.
1013020133131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 1013020133131 its reverse (1313310203101), we get a palindrome (2326330336232).
The spelling of 1013020133131 in words is "one trillion, thirteen billion, twenty million, one hundred thirty-three thousand, one hundred thirty-one".
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