1013024113 has 2 divisors, whose sum is σ = 1013024114. Its totient is φ = 1013024112.

The previous prime is 1013024087. The next prime is 1013024149. The reversal of 1013024113 is 3114203101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 996475489 + 16548624 = 31567^2 + 4068^2 .

It is a cyclic number.

It is not a de Polignac number, because 1013024113 - 2⁹ = 1013023601 is a prime.

It is not a weakly prime, because it can be changed into another prime (1013024413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506512056 + 506512057.

It is an arithmetic number, because the mean of its divisors is an integer number (506512057).

Almost surely, 2^1013024113 is an apocalyptic number.

It is an amenable number.

1013024113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1013024113 is an equidigital number, since it uses as much as digits as its factorization.

1013024113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 1013024113 is about 31828.0397291445. The cubic root of 1013024113 is about 1004.3226586983.

Adding to 1013024113 its reverse (3114203101), we get a palindrome (4127227214).

It can be divided in two parts, 10130 and 24113, that added together give a palindrome (34243).

The spelling of 1013024113 in words is "one billion, thirteen million, twenty-four thousand, one hundred thirteen".