Base | Representation |
---|---|
bin | 10010110111101101… |
… | …01111100110110011 |
3 | 222011001021201211101 |
4 | 21123312233212303 |
5 | 131222014341034 |
6 | 4353142425231 |
7 | 506025116122 |
oct | 113366574663 |
9 | 28131251741 |
10 | 10131012019 |
11 | 4329768307 |
12 | 1b68a32217 |
13 | c55b9b78b |
14 | 6c1707ab9 |
15 | 3e463b514 |
hex | 25bdaf9b3 |
10131012019 has 2 divisors, whose sum is σ = 10131012020. Its totient is φ = 10131012018.
The previous prime is 10131011993. The next prime is 10131012049. The reversal of 10131012019 is 91021013101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10131012019 - 221 = 10128914867 is a prime.
It is a super-2 number, since 2×101310120192 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10131011987 and 10131012005.
It is not a weakly prime, because it can be changed into another prime (10131012049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065506009 + 5065506010.
It is an arithmetic number, because the mean of its divisors is an integer number (5065506010).
Almost surely, 210131012019 is an apocalyptic number.
10131012019 is a deficient number, since it is larger than the sum of its proper divisors (1).
10131012019 is an equidigital number, since it uses as much as digits as its factorization.
10131012019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 19.
The spelling of 10131012019 in words is "ten billion, one hundred thirty-one million, twelve thousand, nineteen".
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