10131113114041 has 2 divisors, whose sum is σ = 10131113114042. Its totient is φ = 10131113114040.

The previous prime is 10131113113967. The next prime is 10131113114047. The reversal of 10131113114041 is 14041131113101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5730469945600 + 4400643168441 = 2393840^2 + 2097771^2 .

It is an emirp because it is prime and its reverse (14041131113101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10131113114041 - 2¹¹ = 10131113111993 is a prime.

It is not a weakly prime, because it can be changed into another prime (10131113114047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065556557020 + 5065556557021.

It is an arithmetic number, because the mean of its divisors is an integer number (5065556557021).

Almost surely, 2^{10131113114041} is an apocalyptic number.

It is an amenable number.

10131113114041 is a deficient number, since it is larger than the sum of its proper divisors (1).

10131113114041 is an equidigital number, since it uses as much as digits as its factorization.

10131113114041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 22.

Adding to 10131113114041 its reverse (14041131113101), we get a palindrome (24172244227142).

The spelling of 10131113114041 in words is "ten trillion, one hundred thirty-one billion, one hundred thirteen million, one hundred fourteen thousand, forty-one".