10131121320017 has 2 divisors, whose sum is σ = 10131121320018. Its totient is φ = 10131121320016.

The previous prime is 10131121319993. The next prime is 10131121320097. The reversal of 10131121320017 is 71002312113101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7973304279616 + 2157817040401 = 2823704^2 + 1468951^2 .

It is an emirp because it is prime and its reverse (71002312113101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10131121320017 - 2¹⁸ = 10131121057873 is a prime.

It is a super-3 number, since 3×10131121320017³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10131121319974 and 10131121320001.

It is not a weakly prime, because it can be changed into another prime (10131121320097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065560660008 + 5065560660009.

It is an arithmetic number, because the mean of its divisors is an integer number (5065560660009).

Almost surely, 2^{10131121320017} is an apocalyptic number.

It is an amenable number.

10131121320017 is a deficient number, since it is larger than the sum of its proper divisors (1).

10131121320017 is an equidigital number, since it uses as much as digits as its factorization.

10131121320017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 23.

Adding to 10131121320017 its reverse (71002312113101), we get a palindrome (81133433433118).

The spelling of 10131121320017 in words is "ten trillion, one hundred thirty-one billion, one hundred twenty-one million, three hundred twenty thousand, seventeen".