10131284495113 has 2 divisors, whose sum is σ = 10131284495114. Its totient is φ = 10131284495112.

The previous prime is 10131284495021. The next prime is 10131284495131. The reversal of 10131284495113 is 31159448213101.

Together with next prime (10131284495131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7465944182544 + 2665340312569 = 2732388^2 + 1632587^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10131284495113 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10131284495113.

It is not a weakly prime, because it can be changed into another prime (10131284495513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065642247556 + 5065642247557.

It is an arithmetic number, because the mean of its divisors is an integer number (5065642247557).

Almost surely, 2^{10131284495113} is an apocalyptic number.

It is an amenable number.

10131284495113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10131284495113 is an equidigital number, since it uses as much as digits as its factorization.

10131284495113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 103680, while the sum is 43.

The spelling of 10131284495113 in words is "ten trillion, one hundred thirty-one billion, two hundred eighty-four million, four hundred ninety-five thousand, one hundred thirteen".