Base | Representation |
---|---|
bin | 101111001011011100… |
… | …0000010101000111001 |
3 | 100200111212000201220201 |
4 | 1132112320002220321 |
5 | 3124443233133311 |
6 | 114313235122201 |
7 | 10214456501635 |
oct | 1362670025071 |
9 | 320455021821 |
10 | 101315521081 |
11 | 39a70a74605 |
12 | 17776443361 |
13 | 9728220298 |
14 | 4c91a61dc5 |
15 | 297e9939c1 |
hex | 1796e02a39 |
101315521081 has 2 divisors, whose sum is σ = 101315521082. Its totient is φ = 101315521080.
The previous prime is 101315521063. The next prime is 101315521091. The reversal of 101315521081 is 180125513101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 61038643600 + 40276877481 = 247060^2 + 200691^2 .
It is a cyclic number.
It is not a de Polignac number, because 101315521081 - 27 = 101315520953 is a prime.
It is a super-3 number, since 3×1013155210813 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (101315521031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50657760540 + 50657760541.
It is an arithmetic number, because the mean of its divisors is an integer number (50657760541).
Almost surely, 2101315521081 is an apocalyptic number.
It is an amenable number.
101315521081 is a deficient number, since it is larger than the sum of its proper divisors (1).
101315521081 is an equidigital number, since it uses as much as digits as its factorization.
101315521081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1200, while the sum is 28.
The spelling of 101315521081 in words is "one hundred one billion, three hundred fifteen million, five hundred twenty-one thousand, eighty-one".
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