10132012020133 has 4 divisors (see below), whose sum is σ = 10182926653600. Its totient is φ = 10081097386668.

The previous prime is 10132012020101. The next prime is 10132012020149. The reversal of 10132012020133 is 33102021023101.

10132012020133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10132012020133 - 2⁵ = 10132012020101 is a prime.

It is a super-2 number, since 2×10132012020133² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10132012020133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10132012026133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25457316435 + ... + 25457316832.

It is an arithmetic number, because the mean of its divisors is an integer number (2545731663400).

Almost surely, 2^{10132012020133} is an apocalyptic number.

It is an amenable number.

10132012020133 is a deficient number, since it is larger than the sum of its proper divisors (50914633467).

10132012020133 is an equidigital number, since it uses as much as digits as its factorization.

10132012020133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50914633466.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 10132012020133 its reverse (33102021023101), we get a palindrome (43234033043234).

The spelling of 10132012020133 in words is "ten trillion, one hundred thirty-two billion, twelve million, twenty thousand, one hundred thirty-three".