Base | Representation |
---|---|
bin | 11101011111010001011… |
… | …11101110110101101111 |
3 | 10120212022012012210111220 |
4 | 32233220233232311233 |
5 | 113100034332010140 |
6 | 2053245014514423 |
7 | 133126406045640 |
oct | 16575057566557 |
9 | 3525265183456 |
10 | 1013222141295 |
11 | 3607835363a1 |
12 | 144452065a13 |
13 | 747146a77a0 |
14 | 3707c4b96c7 |
15 | 1b552447bd0 |
hex | ebe8beed6f |
1013222141295 has 64 divisors (see below), whose sum is σ = 1996024633344. Its totient is φ = 427395386880.
The previous prime is 1013222141263. The next prime is 1013222141377. The reversal of 1013222141295 is 5921412223101.
It is not a de Polignac number, because 1013222141295 - 25 = 1013222141263 is a prime.
It is a super-2 number, since 2×10132221412952 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3495625 + ... + 3774365.
It is an arithmetic number, because the mean of its divisors is an integer number (31187884896).
Almost surely, 21013222141295 is an apocalyptic number.
1013222141295 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1013222141295 is a deficient number, since it is larger than the sum of its proper divisors (982802492049).
1013222141295 is a wasteful number, since it uses less digits than its factorization.
1013222141295 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 281432.
The product of its (nonzero) digits is 8640, while the sum is 33.
Adding to 1013222141295 its reverse (5921412223101), we get a palindrome (6934634364396).
The spelling of 1013222141295 in words is "one trillion, thirteen billion, two hundred twenty-two million, one hundred forty-one thousand, two hundred ninety-five".
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