101323112131 has 2 divisors, whose sum is σ = 101323112132. Its totient is φ = 101323112130.

The previous prime is 101323112119. The next prime is 101323112263. The reversal of 101323112131 is 131211323101.

It is a weak prime.

It is an emirp because it is prime and its reverse (131211323101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101323112131 - 2¹³ = 101323103939 is a prime.

It is a super-2 number, since 2×101323112131² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101323112099 and 101323112108.

It is not a weakly prime, because it can be changed into another prime (101323118131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50661556065 + 50661556066.

It is an arithmetic number, because the mean of its divisors is an integer number (50661556066).

Almost surely, 2^101323112131 is an apocalyptic number.

101323112131 is a deficient number, since it is larger than the sum of its proper divisors (1).

101323112131 is an equidigital number, since it uses as much as digits as its factorization.

101323112131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 101323112131 its reverse (131211323101), we get a palindrome (232534435232).

The spelling of 101323112131 in words is "one hundred one billion, three hundred twenty-three million, one hundred twelve thousand, one hundred thirty-one".