Base | Representation |
---|---|
bin | 10111000010011101101110… |
… | …110110000000011000000011 |
3 | 111021202112001221220122021001 |
4 | 113002131232312000120003 |
5 | 101240044414340143021 |
6 | 555255445121112431 |
7 | 30225306624045016 |
oct | 2702355666003003 |
9 | 437675057818231 |
10 | 101324433131011 |
11 | 2a3154a5a86322 |
12 | b44542b788717 |
13 | 446cb121ab14c |
14 | 1b041b334337d |
15 | baaa33741091 |
hex | 5c276ed80603 |
101324433131011 has 2 divisors, whose sum is σ = 101324433131012. Its totient is φ = 101324433131010.
The previous prime is 101324433130931. The next prime is 101324433131023. The reversal of 101324433131011 is 110131334423101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101324433131011 - 229 = 101323896260099 is a prime.
It is not a weakly prime, because it can be changed into another prime (101324433131081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50662216565505 + 50662216565506.
It is an arithmetic number, because the mean of its divisors is an integer number (50662216565506).
Almost surely, 2101324433131011 is an apocalyptic number.
101324433131011 is a deficient number, since it is larger than the sum of its proper divisors (1).
101324433131011 is an equidigital number, since it uses as much as digits as its factorization.
101324433131011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 28.
Adding to 101324433131011 its reverse (110131334423101), we get a palindrome (211455767554112).
The spelling of 101324433131011 in words is "one hundred one trillion, three hundred twenty-four billion, four hundred thirty-three million, one hundred thirty-one thousand, eleven".
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