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101324913593 is a prime number
BaseRepresentation
bin101111001011101101…
…1110111101110111001
3100200112111200221000112
41132113123313232321
53130003134213333
6114314212314105
710214632361231
oct1362733675671
9320474627015
10101324913593
1139a762aa312
1217779612935
13972a15b497
144c92dc8cc1
1529806eb948
hex17976f7bb9

101324913593 has 2 divisors, whose sum is σ = 101324913594. Its totient is φ = 101324913592.

The previous prime is 101324913559. The next prime is 101324913647. The reversal of 101324913593 is 395319423101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98691479104 + 2633434489 = 314152^2 + 51317^2 .

It is a cyclic number.

It is not a de Polignac number, because 101324913593 - 210 = 101324912569 is a prime.

It is a super-2 number, since 2×1013249135932 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 101324913593.

It is not a weakly prime, because it can be changed into another prime (101324913523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50662456796 + 50662456797.

It is an arithmetic number, because the mean of its divisors is an integer number (50662456797).

Almost surely, 2101324913593 is an apocalyptic number.

It is an amenable number.

101324913593 is a deficient number, since it is larger than the sum of its proper divisors (1).

101324913593 is an equidigital number, since it uses as much as digits as its factorization.

101324913593 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 87480, while the sum is 41.

The spelling of 101324913593 in words is "one hundred one billion, three hundred twenty-four million, nine hundred thirteen thousand, five hundred ninety-three".