Base | Representation |
---|---|
bin | 1001001101110100011100… |
… | …0100000110110010110001 |
3 | 1022212201002121000222112011 |
4 | 2103131013010012302301 |
5 | 2312004411122010001 |
6 | 33315013431402521 |
7 | 2064041453542135 |
oct | 223350704066261 |
9 | 38781077028464 |
10 | 10133020110001 |
11 | 3257431759528 |
12 | 1177a1bb23441 |
13 | 586702935a99 |
14 | 2706257573c5 |
15 | 1288b2ebdd51 |
hex | 93747106cb1 |
10133020110001 has 2 divisors, whose sum is σ = 10133020110002. Its totient is φ = 10133020110000.
The previous prime is 10133020109969. The next prime is 10133020110091. The reversal of 10133020110001 is 10001102033101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6959972606976 + 3173047503025 = 2638176^2 + 1781305^2 .
It is an emirp because it is prime and its reverse (10001102033101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10133020110001 - 25 = 10133020109969 is a prime.
It is not a weakly prime, because it can be changed into another prime (10133020110091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5066510055000 + 5066510055001.
It is an arithmetic number, because the mean of its divisors is an integer number (5066510055001).
Almost surely, 210133020110001 is an apocalyptic number.
It is an amenable number.
10133020110001 is a deficient number, since it is larger than the sum of its proper divisors (1).
10133020110001 is an equidigital number, since it uses as much as digits as its factorization.
10133020110001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 10133020110001 its reverse (10001102033101), we get a palindrome (20134122143102).
The spelling of 10133020110001 in words is "ten trillion, one hundred thirty-three billion, twenty million, one hundred ten thousand, one".
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