1013310120113 has 2 divisors, whose sum is σ = 1013310120114. Its totient is φ = 1013310120112.

The previous prime is 1013310120103. The next prime is 1013310120131. The reversal of 1013310120113 is 3110210133101.

Together with next prime (1013310120131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 812509340449 + 200800779664 = 901393^2 + 448108^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1013310120113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1013310120091 and 1013310120100.

It is not a weakly prime, because it can be changed into another prime (1013310120103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506655060056 + 506655060057.

It is an arithmetic number, because the mean of its divisors is an integer number (506655060057).

Almost surely, 2^{1013310120113} is an apocalyptic number.

It is an amenable number.

1013310120113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1013310120113 is an equidigital number, since it uses as much as digits as its factorization.

1013310120113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1013310120113 its reverse (3110210133101), we get a palindrome (4123520253214).

The spelling of 1013310120113 in words is "one trillion, thirteen billion, three hundred ten million, one hundred twenty thousand, one hundred thirteen".