Search a number
-
+
10133130022234 = 25066565011117
BaseRepresentation
bin1001001101110100110110…
…0111011000110101011010
31022212201101020212002202121
42103131031213120311122
52312010122241202414
633315032355251454
72064044260020022
oct223351547306532
938781336762677
1010133130022234
11325748880018a
121177a508a9b8a
1358671c63a1cb
142706361a8a82
151288bc980724
hex9374d9d8d5a

10133130022234 has 4 divisors (see below), whose sum is σ = 15199695033354. Its totient is φ = 5066565011116.

The previous prime is 10133130022207. The next prime is 10133130022247. The reversal of 10133130022234 is 43222003133101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 8088364440025 + 2044765582209 = 2844005^2 + 1429953^2 .

It is a junction number, because it is equal to n+sod(n) for n = 10133130022199 and 10133130022208.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2533282505557 + ... + 2533282505560.

Almost surely, 210133130022234 is an apocalyptic number.

10133130022234 is a deficient number, since it is larger than the sum of its proper divisors (5066565011120).

10133130022234 is an equidigital number, since it uses as much as digits as its factorization.

10133130022234 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5066565011119.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 10133130022234 its reverse (43222003133101), we get a palindrome (53355133155335).

The spelling of 10133130022234 in words is "ten trillion, one hundred thirty-three billion, one hundred thirty million, twenty-two thousand, two hundred thirty-four".

Divisors: 1 2 5066565011117 10133130022234