1013320214 has 4 divisors (see below), whose sum is σ = 1519980324. Its totient is φ = 506660106.

The previous prime is 1013320213. The next prime is 1013320229. The reversal of 1013320214 is 4120233101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 4120233101 = 17 ⋅242366653.

It is a super-2 number, since 2×1013320214² = 2053635712202011592, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1013320192 and 1013320201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1013320211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 253330052 + ... + 253330055.

It is an arithmetic number, because the mean of its divisors is an integer number (379995081).

Almost surely, 2^1013320214 is an apocalyptic number.

1013320214 is a deficient number, since it is larger than the sum of its proper divisors (506660110).

1013320214 is an equidigital number, since it uses as much as digits as its factorization.

1013320214 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 506660109.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 1013320214 is about 31832.6909638504. The cubic root of 1013320214 is about 1004.4205017046.

Adding to 1013320214 its reverse (4120233101), we get a palindrome (5133553315).

The spelling of 1013320214 in words is "one billion, thirteen million, three hundred twenty thousand, two hundred fourteen".