Base | Representation |
---|---|
bin | 10010110111111110… |
… | …10011010010011011 |
3 | 222011012111201001201 |
4 | 21123333103102123 |
5 | 131223103132243 |
6 | 4353302455031 |
7 | 506053151302 |
oct | 113377232233 |
9 | 28135451051 |
10 | 10133255323 |
11 | 432aa5a784 |
12 | 1b69734477 |
13 | c564a5889 |
14 | 6c1b2d439 |
15 | 3e493104d |
hex | 25bfd349b |
10133255323 has 2 divisors, whose sum is σ = 10133255324. Its totient is φ = 10133255322.
The previous prime is 10133255317. The next prime is 10133255357. The reversal of 10133255323 is 32355233101.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10133255323 is a prime.
It is a super-2 number, since 2×101332553232 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10133255291 and 10133255300.
It is not a weakly prime, because it can be changed into another prime (10133255303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5066627661 + 5066627662.
It is an arithmetic number, because the mean of its divisors is an integer number (5066627662).
Almost surely, 210133255323 is an apocalyptic number.
10133255323 is a deficient number, since it is larger than the sum of its proper divisors (1).
10133255323 is an equidigital number, since it uses as much as digits as its factorization.
10133255323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8100, while the sum is 28.
Adding to 10133255323 its reverse (32355233101), we get a palindrome (42488488424).
The spelling of 10133255323 in words is "ten billion, one hundred thirty-three million, two hundred fifty-five thousand, three hundred twenty-three".
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