101333022311131 has 4 divisors (see below), whose sum is σ = 109127870181232. Its totient is φ = 93538174441032.

The previous prime is 101333022311077. The next prime is 101333022311161. The reversal of 101333022311131 is 131113220333101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 101333022311131 - 2¹⁵ = 101333022278363 is a prime.

It is a super-2 number, since 2×101333022311131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101333022311096 and 101333022311105.

It is not an unprimeable number, because it can be changed into a prime (101333022311161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3897423935031 + ... + 3897423935056.

It is an arithmetic number, because the mean of its divisors is an integer number (27281967545308).

Almost surely, 2^{101333022311131} is an apocalyptic number.

101333022311131 is a deficient number, since it is larger than the sum of its proper divisors (7794847870101).

101333022311131 is an equidigital number, since it uses as much as digits as its factorization.

101333022311131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7794847870100.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 101333022311131 its reverse (131113220333101), we get a palindrome (232446242644232).

The spelling of 101333022311131 in words is "one hundred one trillion, three hundred thirty-three billion, twenty-two million, three hundred eleven thousand, one hundred thirty-one".