10133311302321 has 4 divisors (see below), whose sum is σ = 13511081736432. Its totient is φ = 6755540868212.

The previous prime is 10133311302311. The next prime is 10133311302337. The reversal of 10133311302321 is 12320311333101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10133311302321 - 2⁹ = 10133311301809 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10133311302291 and 10133311302300.

It is not an unprimeable number, because it can be changed into a prime (10133311302311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1688885217051 + ... + 1688885217056.

It is an arithmetic number, because the mean of its divisors is an integer number (3377770434108).

Almost surely, 2^{10133311302321} is an apocalyptic number.

It is an amenable number.

10133311302321 is a deficient number, since it is larger than the sum of its proper divisors (3377770434111).

10133311302321 is an equidigital number, since it uses as much as digits as its factorization.

10133311302321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3377770434110.

The product of its (nonzero) digits is 972, while the sum is 24.

Adding to 10133311302321 its reverse (12320311333101), we get a palindrome (22453622635422).

The spelling of 10133311302321 in words is "ten trillion, one hundred thirty-three billion, three hundred eleven million, three hundred two thousand, three hundred twenty-one".