101333443132114 has 4 divisors (see below), whose sum is σ = 152000164698174. Its totient is φ = 50666721566056.

The previous prime is 101333443132081. The next prime is 101333443132139. The reversal of 101333443132114 is 411231344333101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 50675106636025 + 50658336496089 = 7118645^2 + 7117467^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 101333443132114.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25333360783027 + ... + 25333360783030.

Almost surely, 2^{101333443132114} is an apocalyptic number.

101333443132114 is a deficient number, since it is larger than the sum of its proper divisors (50666721566060).

101333443132114 is an equidigital number, since it uses as much as digits as its factorization.

101333443132114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50666721566059.

The product of its (nonzero) digits is 31104, while the sum is 34.

Adding to 101333443132114 its reverse (411231344333101), we get a palindrome (512564787465215).

The spelling of 101333443132114 in words is "one hundred one trillion, three hundred thirty-three billion, four hundred forty-three million, one hundred thirty-two thousand, one hundred fourteen".