Base | Representation |
---|---|
bin | 11101011111100110111… |
… | …10000011001110001011 |
3 | 10120212202201202101111022 |
4 | 32233303132003032023 |
5 | 113100421411234223 |
6 | 2053314523023055 |
7 | 133134022226222 |
oct | 16576336031613 |
9 | 3525681671438 |
10 | 1013402055563 |
11 | 36086604a677 |
12 | 1444a236aa8b |
13 | 74742a4b631 |
14 | 3709834dcb9 |
15 | 1b563135ac8 |
hex | ebf378338b |
1013402055563 has 2 divisors, whose sum is σ = 1013402055564. Its totient is φ = 1013402055562.
The previous prime is 1013402055493. The next prime is 1013402055581. The reversal of 1013402055563 is 3655502043101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1013402055563 - 214 = 1013402039179 is a prime.
It is not a weakly prime, because it can be changed into another prime (1013402055163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506701027781 + 506701027782.
It is an arithmetic number, because the mean of its divisors is an integer number (506701027782).
Almost surely, 21013402055563 is an apocalyptic number.
1013402055563 is a deficient number, since it is larger than the sum of its proper divisors (1).
1013402055563 is an equidigital number, since it uses as much as digits as its factorization.
1013402055563 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54000, while the sum is 35.
Adding to 1013402055563 its reverse (3655502043101), we get a palindrome (4668904098664).
The spelling of 1013402055563 in words is "one trillion, thirteen billion, four hundred two million, fifty-five thousand, five hundred sixty-three".
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