101344143331 has 2 divisors, whose sum is σ = 101344143332. Its totient is φ = 101344143330.

The previous prime is 101344143289. The next prime is 101344143353. The reversal of 101344143331 is 133341443101.

It is a strong prime.

It is an emirp because it is prime and its reverse (133341443101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101344143331 - 2¹⁵ = 101344110563 is a prime.

It is a super-2 number, since 2×101344143331² (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 101344143331.

It is not a weakly prime, because it can be changed into another prime (101344143361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50672071665 + 50672071666.

It is an arithmetic number, because the mean of its divisors is an integer number (50672071666).

Almost surely, 2^101344143331 is an apocalyptic number.

101344143331 is a deficient number, since it is larger than the sum of its proper divisors (1).

101344143331 is an equidigital number, since it uses as much as digits as its factorization.

101344143331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 101344143331 its reverse (133341443101), we get a palindrome (234685586432).

The spelling of 101344143331 in words is "one hundred one billion, three hundred forty-four million, one hundred forty-three thousand, three hundred thirty-one".