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10134551510131 is a prime number
BaseRepresentation
bin1001001101111010001001…
…0101111011110001110011
31022212212001022122011120111
42103132202111323301303
52312021030141311011
633315425414522151
72064124430326426
oct223364225736163
938785038564514
1010134551510131
113258048136074
121178188966357
135868b7ca03c9
1427072ccb19bd
1512895266c121
hex937a257bc73

10134551510131 has 2 divisors, whose sum is σ = 10134551510132. Its totient is φ = 10134551510130.

The previous prime is 10134551510101. The next prime is 10134551510147. The reversal of 10134551510131 is 13101515543101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10134551510131 - 25 = 10134551510099 is a prime.

It is a super-2 number, since 2×101345515101312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10134551510093 and 10134551510102.

It is not a weakly prime, because it can be changed into another prime (10134551510101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5067275755065 + 5067275755066.

It is an arithmetic number, because the mean of its divisors is an integer number (5067275755066).

Almost surely, 210134551510131 is an apocalyptic number.

10134551510131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10134551510131 is an equidigital number, since it uses as much as digits as its factorization.

10134551510131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4500, while the sum is 31.

The spelling of 10134551510131 in words is "ten trillion, one hundred thirty-four billion, five hundred fifty-one million, five hundred ten thousand, one hundred thirty-one".