1014011313132 has 24 divisors (see below), whose sum is σ = 2366302945216. Its totient is φ = 337964264208.

The previous prime is 1014011313079. The next prime is 1014011313169. The reversal of 1014011313132 is 2313131104101.

It is a junction number, because it is equal to n+sod(n) for n = 1014011313099 and 1014011313108.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4831318 + ... + 5036829.

Almost surely, 2^{1014011313132} is an apocalyptic number.

1014011313132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1014011313132 is an abundant number, since it is smaller than the sum of its proper divisors (1352291632084).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1014011313132 is a wasteful number, since it uses less digits than its factorization.

1014011313132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9876717 (or 9876715 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 1014011313132 its reverse (2313131104101), we get a palindrome (3327142417233).

The spelling of 1014011313132 in words is "one trillion, fourteen billion, eleven million, three hundred thirteen thousand, one hundred thirty-two".