1014114211301 has 4 divisors (see below), whose sum is σ = 1014116546400. Its totient is φ = 1014111876204.

The previous prime is 1014114211213. The next prime is 1014114211303. The reversal of 1014114211301 is 1031124114101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1014114211301 - 2³⁰ = 1013040469477 is a prime.

It is a super-2 number, since 2×1014114211301² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1014114211303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 302441 + ... + 1455918.

It is an arithmetic number, because the mean of its divisors is an integer number (253529136600).

Almost surely, 2^{1014114211301} is an apocalyptic number.

It is an amenable number.

1014114211301 is a deficient number, since it is larger than the sum of its proper divisors (2335099).

1014114211301 is an equidigital number, since it uses as much as digits as its factorization.

1014114211301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2335098.

The product of its (nonzero) digits is 96, while the sum is 20.

Adding to 1014114211301 its reverse (1031124114101), we get a palindrome (2045238325402).

The spelling of 1014114211301 in words is "one trillion, fourteen billion, one hundred fourteen million, two hundred eleven thousand, three hundred one".