Search a number
-
+
10142018 = 25071009
BaseRepresentation
bin100110101100…
…000101000010
3201002021020022
4212230011002
510044021033
61001213442
7152130365
oct46540502
921067208
1010142018
1157a7937
123491282
1321413c3
1414c00dc
15d55098
hex9ac142

10142018 has 4 divisors (see below), whose sum is σ = 15213030. Its totient is φ = 5071008.

The previous prime is 10142017. The next prime is 10142051. The reversal of 10142018 is 81024101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 81024101 = 233522787.

It can be written as a sum of positive squares in only one way, i.e., 7912969 + 2229049 = 2813^2 + 1493^2 .

It is a super-2 number, since 2×101420182 = 205721058224648, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10141987 and 10142005.

It is not an unprimeable number, because it can be changed into a prime (10142017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2535503 + ... + 2535506.

Almost surely, 210142018 is an apocalyptic number.

10142018 is a deficient number, since it is larger than the sum of its proper divisors (5071012).

10142018 is an equidigital number, since it uses as much as digits as its factorization.

10142018 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5071011.

The product of its (nonzero) digits is 64, while the sum is 17.

The square root of 10142018 is about 3184.6535133355. The cubic root of 10142018 is about 216.4585736439.

Adding to 10142018 its reverse (81024101), we get a palindrome (91166119).

The spelling of 10142018 in words is "ten million, one hundred forty-two thousand, eighteen".

Divisors: 1 2 5071009 10142018