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10142112340433 is a prime number
BaseRepresentation
bin1001001110010110010100…
…0000001101100111010001
31022220120120020200010220102
42103211211000031213101
52312132021224343213
633323115545422145
72064512666325443
oct223454500154721
938816506603812
1010142112340433
113260278014857
121179738a9a955
135875215392a8
14270c490da493
15128c46318158
hex9396500d9d1

10142112340433 has 2 divisors, whose sum is σ = 10142112340434. Its totient is φ = 10142112340432.

The previous prime is 10142112340397. The next prime is 10142112340453. The reversal of 10142112340433 is 33404321124101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6678668513344 + 3463443827089 = 2584312^2 + 1861033^2 .

It is a cyclic number.

It is not a de Polignac number, because 10142112340433 - 210 = 10142112339409 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10142112340396 and 10142112340405.

It is not a weakly prime, because it can be changed into another prime (10142112340453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5071056170216 + 5071056170217.

It is an arithmetic number, because the mean of its divisors is an integer number (5071056170217).

Almost surely, 210142112340433 is an apocalyptic number.

It is an amenable number.

10142112340433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10142112340433 is an equidigital number, since it uses as much as digits as its factorization.

10142112340433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 10142112340433 its reverse (33404321124101), we get a palindrome (43546433464534).

The spelling of 10142112340433 in words is "ten trillion, one hundred forty-two billion, one hundred twelve million, three hundred forty thousand, four hundred thirty-three".