10142400113 has 4 divisors (see below), whose sum is σ = 10142603940. Its totient is φ = 10142196288.

The previous prime is 10142400097. The next prime is 10142400119. The reversal of 10142400113 is 31100424101.

It is a happy number.

10142400113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31100424101 = 2089 ⋅14887709.

It can be written as a sum of positive squares in 2 ways, for example, as 2565219904 + 7577180209 = 50648^2 + 87047^2 .

It is a cyclic number.

It is not a de Polignac number, because 10142400113 - 2⁴ = 10142400097 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10142400091 and 10142400100.

It is not an unprimeable number, because it can be changed into a prime (10142400119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27533 + ... + 145061.

It is an arithmetic number, because the mean of its divisors is an integer number (2535650985).

Almost surely, 2^10142400113 is an apocalyptic number.

It is an amenable number.

10142400113 is a deficient number, since it is larger than the sum of its proper divisors (203827).

10142400113 is an equidigital number, since it uses as much as digits as its factorization.

10142400113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 203826.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 10142400113 its reverse (31100424101), we get a palindrome (41242824214).

The spelling of 10142400113 in words is "ten billion, one hundred forty-two million, four hundred thousand, one hundred thirteen".