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10143121441 is a prime number
BaseRepresentation
bin10010111001001001…
…11100000000100001
3222011220001221211111
421130210330000201
5131233114341231
64354254143321
7506233052425
oct113444740041
928156057744
1010143121441
1143355892a2
121b70ab1b41
13c5854b50b
146c317ab85
153e572e4b1
hex25c93c021

10143121441 has 2 divisors, whose sum is σ = 10143121442. Its totient is φ = 10143121440.

The previous prime is 10143121427. The next prime is 10143121447. The reversal of 10143121441 is 14412134101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8614624225 + 1528497216 = 92815^2 + 39096^2 .

It is an emirp because it is prime and its reverse (14412134101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10143121441 - 213 = 10143113249 is a prime.

It is not a weakly prime, because it can be changed into another prime (10143121447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5071560720 + 5071560721.

It is an arithmetic number, because the mean of its divisors is an integer number (5071560721).

Almost surely, 210143121441 is an apocalyptic number.

It is an amenable number.

10143121441 is a deficient number, since it is larger than the sum of its proper divisors (1).

10143121441 is an equidigital number, since it uses as much as digits as its factorization.

10143121441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 10143121441 its reverse (14412134101), we get a palindrome (24555255542).

The spelling of 10143121441 in words is "ten billion, one hundred forty-three million, one hundred twenty-one thousand, four hundred forty-one".