10143311014 has 4 divisors (see below), whose sum is σ = 15214966524. Its totient is φ = 5071655506.

The previous prime is 10143310981. The next prime is 10143311023. The reversal of 10143311014 is 41011334101.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 10143310982 and 10143311000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2535827752 + ... + 2535827755.

It is an arithmetic number, because the mean of its divisors is an integer number (3803741631).

Almost surely, 2^10143311014 is an apocalyptic number.

10143311014 is a deficient number, since it is larger than the sum of its proper divisors (5071655510).

10143311014 is an equidigital number, since it uses as much as digits as its factorization.

10143311014 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5071655509.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 10143311014 its reverse (41011334101), we get a palindrome (51154645115).

The spelling of 10143311014 in words is "ten billion, one hundred forty-three million, three hundred eleven thousand, fourteen".