10143313241 has 2 divisors, whose sum is σ = 10143313242. Its totient is φ = 10143313240.

The previous prime is 10143313139. The next prime is 10143313261. The reversal of 10143313241 is 14231334101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5960457616 + 4182855625 = 77204^2 + 64675^2 .

It is an emirp because it is prime and its reverse (14231334101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10143313241 - 2¹⁰ = 10143312217 is a prime.

It is not a weakly prime, because it can be changed into another prime (10143313261) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5071656620 + 5071656621.

It is an arithmetic number, because the mean of its divisors is an integer number (5071656621).

Almost surely, 2^10143313241 is an apocalyptic number.

It is an amenable number.

10143313241 is a deficient number, since it is larger than the sum of its proper divisors (1).

10143313241 is an equidigital number, since it uses as much as digits as its factorization.

10143313241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 10143313241 its reverse (14231334101), we get a palindrome (24374647342).

The spelling of 10143313241 in words is "ten billion, one hundred forty-three million, three hundred thirteen thousand, two hundred forty-one".