Base | Representation |
---|---|
bin | 1001001110011010110100… |
… | …1010111110001001101001 |
3 | 1022220200200121222010112201 |
4 | 2103212231022332021221 |
5 | 2312142011204321413 |
6 | 33323440040540201 |
7 | 2064555000641632 |
oct | 223465512761151 |
9 | 38820617863481 |
10 | 10143323120233 |
11 | 3260839513616 |
12 | 1179a16481661 |
13 | 587685336244 |
14 | 270d21c34889 |
15 | 128cb77829dd |
hex | 939ad2be269 |
10143323120233 has 2 divisors, whose sum is σ = 10143323120234. Its totient is φ = 10143323120232.
The previous prime is 10143323120221. The next prime is 10143323120257. The reversal of 10143323120233 is 33202132334101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9583711403049 + 559611717184 = 3095757^2 + 748072^2 .
It is a cyclic number.
It is not a de Polignac number, because 10143323120233 - 25 = 10143323120201 is a prime.
It is not a weakly prime, because it can be changed into another prime (10143323127233) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5071661560116 + 5071661560117.
It is an arithmetic number, because the mean of its divisors is an integer number (5071661560117).
Almost surely, 210143323120233 is an apocalyptic number.
It is an amenable number.
10143323120233 is a deficient number, since it is larger than the sum of its proper divisors (1).
10143323120233 is an equidigital number, since it uses as much as digits as its factorization.
10143323120233 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 28.
Adding to 10143323120233 its reverse (33202132334101), we get a palindrome (43345455454334).
The spelling of 10143323120233 in words is "ten trillion, one hundred forty-three billion, three hundred twenty-three million, one hundred twenty thousand, two hundred thirty-three".
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