Base | Representation |
---|---|
bin | 10010111001001110… |
… | …10000110110001011 |
3 | 222011221012221002211 |
4 | 21130213100312023 |
5 | 131233243343313 |
6 | 4354315205551 |
7 | 506241202003 |
oct | 113447206613 |
9 | 28157187084 |
10 | 10143731083 |
11 | 4335965332 |
12 | 1b711468b7 |
13 | c58702b55 |
14 | 6c3299003 |
15 | 3e57eee3d |
hex | 25c9d0d8b |
10143731083 has 2 divisors, whose sum is σ = 10143731084. Its totient is φ = 10143731082.
The previous prime is 10143731051. The next prime is 10143731141. The reversal of 10143731083 is 38013734101.
10143731083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10143731083 - 25 = 10143731051 is a prime.
It is not a weakly prime, because it can be changed into another prime (10143731783) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5071865541 + 5071865542.
It is an arithmetic number, because the mean of its divisors is an integer number (5071865542).
Almost surely, 210143731083 is an apocalyptic number.
10143731083 is a deficient number, since it is larger than the sum of its proper divisors (1).
10143731083 is an equidigital number, since it uses as much as digits as its factorization.
10143731083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 31.
The spelling of 10143731083 in words is "ten billion, one hundred forty-three million, seven hundred thirty-one thousand, eighty-three".
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