101440112131 has 4 divisors (see below), whose sum is σ = 102214464264. Its totient is φ = 100665760000.

The previous prime is 101440112101. The next prime is 101440112143. The reversal of 101440112131 is 131211044101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 101440112131 - 2¹³ = 101440103939 is a prime.

It is a super-2 number, since 2×101440112131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101440112099 and 101440112108.

It is not an unprimeable number, because it can be changed into a prime (101440112101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 387175870 + ... + 387176131.

It is an arithmetic number, because the mean of its divisors is an integer number (25553616066).

Almost surely, 2^101440112131 is an apocalyptic number.

101440112131 is a deficient number, since it is larger than the sum of its proper divisors (774352133).

101440112131 is an equidigital number, since it uses as much as digits as its factorization.

101440112131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 774352132.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 101440112131 its reverse (131211044101), we get a palindrome (232651156232).

The spelling of 101440112131 in words is "one hundred one billion, four hundred forty million, one hundred twelve thousand, one hundred thirty-one".