10144012113133 has 4 divisors (see below), whose sum is σ = 10144573286940. Its totient is φ = 10143450939328.

The previous prime is 10144012113127. The next prime is 10144012113227. The reversal of 10144012113133 is 33131121044101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9663282050724 + 480730062409 = 3108582^2 + 693347^2 .

It is a cyclic number.

It is not a de Polignac number, because 10144012113133 - 2⁴¹ = 7944988857581 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10144012113098 and 10144012113107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10144012119133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 280559788 + ... + 280595941.

It is an arithmetic number, because the mean of its divisors is an integer number (2536143321735).

Almost surely, 2^{10144012113133} is an apocalyptic number.

It is an amenable number.

10144012113133 is a deficient number, since it is larger than the sum of its proper divisors (561173807).

10144012113133 is an equidigital number, since it uses as much as digits as its factorization.

10144012113133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 561173806.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 10144012113133 its reverse (33131121044101), we get a palindrome (43275133157234).

The spelling of 10144012113133 in words is "ten trillion, one hundred forty-four billion, twelve million, one hundred thirteen thousand, one hundred thirty-three".