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10144234041433 = 47215834766839
BaseRepresentation
bin1001001110011110001101…
…1101110111000001011001
31022220210001010000201111221
42103213203131313001121
52312200342403311213
633324110301052041
72064616401434602
oct223474335670131
938823033021457
1010144234041433
113261166725158
12117a02b557021
1358779bc8487b
14270daabd4da9
15128d1c71a38d
hex939e3777059

10144234041433 has 4 divisors (see below), whose sum is σ = 10360068808320. Its totient is φ = 9928399274548.

The previous prime is 10144234041419. The next prime is 10144234041481. The reversal of 10144234041433 is 33414043244101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10144234041433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10144234044433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 107917383373 + ... + 107917383466.

It is an arithmetic number, because the mean of its divisors is an integer number (2590017202080).

Almost surely, 210144234041433 is an apocalyptic number.

It is an amenable number.

10144234041433 is a deficient number, since it is larger than the sum of its proper divisors (215834766887).

10144234041433 is an equidigital number, since it uses as much as digits as its factorization.

10144234041433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 215834766886.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 10144234041433 its reverse (33414043244101), we get a palindrome (43558277285534).

The spelling of 10144234041433 in words is "ten trillion, one hundred forty-four billion, two hundred thirty-four million, forty-one thousand, four hundred thirty-three".

Divisors: 1 47 215834766839 10144234041433