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1014431131303 = 23405191088519
BaseRepresentation
bin11101100001100001100…
…11101010011010100111
310120222102110010212000121
432300300303222122213
5113110023332200203
62054005003422411
7133201356226102
oct16606063523247
93528373125017
101014431131303
11361243a22497
1214472ab24a07
1374877cc8ba5
1437154ca9739
151b5c365c0bd
hexec30cea6a7

1014431131303 has 8 divisors (see below), whose sum is σ = 1058563929600. Its totient is φ = 970300591128.

The previous prime is 1014431131271. The next prime is 1014431131321. The reversal of 1014431131303 is 3031311344101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1014431131303 - 25 = 1014431131271 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1014431131403) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 387678 + ... + 1476196.

It is an arithmetic number, because the mean of its divisors is an integer number (132320491200).

Almost surely, 21014431131303 is an apocalyptic number.

1014431131303 is a deficient number, since it is larger than the sum of its proper divisors (44132798297).

1014431131303 is a wasteful number, since it uses less digits than its factorization.

1014431131303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1129061.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1014431131303 its reverse (3031311344101), we get a palindrome (4045742475404).

The spelling of 1014431131303 in words is "one trillion, fourteen billion, four hundred thirty-one million, one hundred thirty-one thousand, three hundred three".

Divisors: 1 23 40519 931937 1088519 25035937 44105701361 1014431131303