10144413141 has 4 divisors (see below), whose sum is σ = 13525884192. Its totient is φ = 6762942092.

The previous prime is 10144413133. The next prime is 10144413161. The reversal of 10144413141 is 14131444101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14131444101 = 3 ⋅4710481367.

It is a cyclic number.

It is not a de Polignac number, because 10144413141 - 2³ = 10144413133 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10144413131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1690735521 + ... + 1690735526.

It is an arithmetic number, because the mean of its divisors is an integer number (3381471048).

Almost surely, 2^10144413141 is an apocalyptic number.

It is an amenable number.

10144413141 is a deficient number, since it is larger than the sum of its proper divisors (3381471051).

10144413141 is an equidigital number, since it uses as much as digits as its factorization.

10144413141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3381471050.

The product of its (nonzero) digits is 768, while the sum is 24.

Adding to 10144413141 its reverse (14131444101), we get a palindrome (24275857242).

The spelling of 10144413141 in words is "ten billion, one hundred forty-four million, four hundred thirteen thousand, one hundred forty-one".