1014600113 has 2 divisors, whose sum is σ = 1014600114. Its totient is φ = 1014600112.

The previous prime is 1014600101. The next prime is 1014600149. The reversal of 1014600113 is 3110064101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1006602529 + 7997584 = 31727^2 + 2828^2 .

It is a cyclic number.

It is not a de Polignac number, because 1014600113 - 2¹⁴ = 1014583729 is a prime.

It is a super-3 number, since 3×1014600113³ (a number of 28 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1014600091 and 1014600100.

It is not a weakly prime, because it can be changed into another prime (1014600413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 507300056 + 507300057.

It is an arithmetic number, because the mean of its divisors is an integer number (507300057).

Almost surely, 2^1014600113 is an apocalyptic number.

It is an amenable number.

1014600113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1014600113 is an equidigital number, since it uses as much as digits as its factorization.

1014600113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 1014600113 is about 31852.7881511179. The cubic root of 1014600113 is about 1004.8432097838.

Adding to 1014600113 its reverse (3110064101), we get a palindrome (4124664214).

The spelling of 1014600113 in words is "one billion, fourteen million, six hundred thousand, one hundred thirteen".