10148403132 has 54 divisors (see below), whose sum is σ = 29841142968. Its totient is φ = 2899543248.

The previous prime is 10148403073. The next prime is 10148403169. The reversal of 10148403132 is 23130484101.

It is a super-2 number, since 2×10148403132² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10148403096 and 10148403105.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 2874768 + ... + 2878295.

Almost surely, 2^10148403132 is an apocalyptic number.

10148403132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

10148403132 is an abundant number, since it is smaller than the sum of its proper divisors (19692739836).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10148403132 is a wasteful number, since it uses less digits than its factorization.

10148403132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5753087 (or 5753075 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 27.

Adding to 10148403132 its reverse (23130484101), we get a palindrome (33278887233).

The spelling of 10148403132 in words is "ten billion, one hundred forty-eight million, four hundred three thousand, one hundred thirty-two".