Base | Representation |
---|---|
bin | 11101100010100110111… |
… | …11101111010101011011 |
3 | 10121000221000020111021001 |
4 | 32301103133233111123 |
5 | 113112221324024011 |
6 | 2054142433325431 |
7 | 133221654043225 |
oct | 16612337572533 |
9 | 3530830214231 |
10 | 1015013111131 |
11 | 361512492558 |
12 | 144871a06877 |
13 | 7493b755556 |
14 | 371ac2c1415 |
15 | 1b6097ba7c1 |
hex | ec537ef55b |
1015013111131 has 2 divisors, whose sum is σ = 1015013111132. Its totient is φ = 1015013111130.
The previous prime is 1015013111117. The next prime is 1015013111153. The reversal of 1015013111131 is 1311113105101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1015013111131 - 211 = 1015013109083 is a prime.
It is a super-2 number, since 2×10150131111312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1015013111099 and 1015013111108.
It is not a weakly prime, because it can be changed into another prime (1015013111111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 507506555565 + 507506555566.
It is an arithmetic number, because the mean of its divisors is an integer number (507506555566).
Almost surely, 21015013111131 is an apocalyptic number.
1015013111131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1015013111131 is an equidigital number, since it uses as much as digits as its factorization.
1015013111131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45, while the sum is 19.
Adding to 1015013111131 its reverse (1311113105101), we get a palindrome (2326126216232).
The spelling of 1015013111131 in words is "one trillion, fifteen billion, thirteen million, one hundred eleven thousand, one hundred thirty-one".
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