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101553345341953 is a prime number
BaseRepresentation
bin10111000101110010111011…
…000100110010101000000001
3111022120101221020121211001221
4113011302323010302220001
5101302322222401420303
6555552543544155041
730250662365533141
oct2705627304625001
9438511836554057
10101553345341953
112a3a3593a5652a
12b481875a68a81
1344885933c873b
141b112cb1cc921
15bb198006b4bd
hex5c5cbb132a01

101553345341953 has 2 divisors, whose sum is σ = 101553345341954. Its totient is φ = 101553345341952.

The previous prime is 101553345341909. The next prime is 101553345341969. The reversal of 101553345341953 is 359143543355101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 88730522017344 + 12822823324609 = 9419688^2 + 3580897^2 .

It is a cyclic number.

It is not a de Polignac number, because 101553345341953 - 213 = 101553345333761 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 101553345341953.

It is not a weakly prime, because it can be changed into another prime (101553345341993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50776672670976 + 50776672670977.

It is an arithmetic number, because the mean of its divisors is an integer number (50776672670977).

Almost surely, 2101553345341953 is an apocalyptic number.

It is an amenable number.

101553345341953 is a deficient number, since it is larger than the sum of its proper divisors (1).

101553345341953 is an equidigital number, since it uses as much as digits as its factorization.

101553345341953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7290000, while the sum is 52.

The spelling of 101553345341953 in words is "one hundred one trillion, five hundred fifty-three billion, three hundred forty-five million, three hundred forty-one thousand, nine hundred fifty-three".