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10155345440113 is a prime number
BaseRepresentation
bin1001001111000111100111…
…0000011110110101110001
31022221211201111002021000101
42103301321300132311301
52312341121413040423
633333145024552401
72065461632656126
oct223617160366561
938854644067011
1010155345440113
11326594882a475
121180210782701
1358884ccb40a3
142717427c274d
1512926ce617ad
hex93c79c1ed71

10155345440113 has 2 divisors, whose sum is σ = 10155345440114. Its totient is φ = 10155345440112.

The previous prime is 10155345439991. The next prime is 10155345440137. The reversal of 10155345440113 is 31104454355101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6144389948944 + 4010955491169 = 2478788^2 + 2002737^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10155345440113 is a prime.

It is not a weakly prime, because it can be changed into another prime (10155343440113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5077672720056 + 5077672720057.

It is an arithmetic number, because the mean of its divisors is an integer number (5077672720057).

Almost surely, 210155345440113 is an apocalyptic number.

It is an amenable number.

10155345440113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10155345440113 is an equidigital number, since it uses as much as digits as its factorization.

10155345440113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72000, while the sum is 37.

Adding to 10155345440113 its reverse (31104454355101), we get a palindrome (41259799795214).

The spelling of 10155345440113 in words is "ten trillion, one hundred fifty-five billion, three hundred forty-five million, four hundred forty thousand, one hundred thirteen".